java如何获取一个文件ACL(访问控制列表)呢?

获取文件的访问控制列表的实现思路

使用Files.getAcl方法即可获取一个文件的访问控制列表

import java.nio.file.Files;
import java.nio.file.Path;
import java.nio.file.Paths;
import java.nio.file.attribute.AclEntry;
import java.nio.file.attribute.AclEntryPermission;
import java.nio.file.attribute.AclEntryType;
import java.util.list;
 
public class FileAclExample {
 
    public static void main(String[] args) throws Exception {
        Path path = Paths.get("java265.txt");
        List acl = Files.getAcl(path);
 
        System.out.println("ACL for " + path);
        for (AclEntry entry : acl) {
            System.out.format("%s:%s %s\n",
                    entry.principal(),
                    entry.type() == AclEntryType.ALLOW ? "ALLOW" : "DENY",
                    entry.permissions());
        }
    }
}

----运行以上代码，将输出以下信息-----
ACL for java265.txt
OWNER:SINGLETON_GROUP ALLOW OWNER_ALL
OWNER:SINGLETON_GROUP ALLOW FILE_READ_DATA, FILE_WRITE_DATA, FILE_APPEND_DATA, FILE_READ_EA, FILE_WRITE_EA, READ_ATTRIBUTES, WRITE_ATTRIBUTES, DELETE, READ_PERMISSIONS, SYNCHRONIZE, READ_ACL, WRITE_ACL, WRITE_OWNER
Everyone ALLOW FILE_READ_DATA