Java如何将“指定路径或文件”压缩为zip文件呢?

Java代码生成压缩文件的实现思路

借助ZipOutputStream对象即可将指定路径压缩为一个压缩文件

 /**
 *  压缩指定文件夹中的所有文件，生成指定名称的zip压缩包
 *
 * @param sourcePath 需要压缩的文件名称列表(包含相对路径)
 * @param zipOutPath 压缩后的文件名称
 **/
public static void batchZipFiles(String sourcePath, String zipOutPath) {
	ZipOutputStream zipOutputStream = null;
	WritableByteChannel writableByteChannel = null;
	MappedByteBuffer mappedByteBuffer = null;
	try {
		zipOutputStream = new ZipOutputStream(new FileOutputStream(zipOutPath));
		writableByteChannel = Channels.newChannel(zipOutputStream);
		File file = new File(sourcePath);
		for (File source : file.listFiles()) {
			long fileSize = source.length();
			//利用putNextEntry来把文件写入
			zipOutputStream.putNextEntry(new ZipEntry(source.getName()));
			long read = Integer.MAX_VALUE;
			int count = (int) Math.ceil((double) fileSize / read);
			long pre = 0;
			//由于一次映射的文件大小不能超过2GB，所以分次映射
			for (int i = 0; i < count; i++) {
				if (fileSize - pre < Integer.MAX_VALUE) {
					read = fileSize - pre;
				}
				mappedByteBuffer = new RandomAccessFile(source, "r").getChannel()
						.map(FileChannel.MapMode.READ_ONLY, pre, read);
				writableByteChannel.write(mappedByteBuffer);
				pre += read;
			}
		}
		mappedByteBuffer.clear();
	} catch (Exception e) {
		log.error("Zip more file error， fileNames: " + sourcePath, e);
	} finally {
		try {
			if (null != zipOutputStream) {
				zipOutputStream.close();
			}
			if (null != writableByteChannel) {
				writableByteChannel.close();
			}
			if (null != mappedByteBuffer) {
				mappedByteBuffer.clear();
			}
		} catch (Exception e) {
			log.error("Zip more file error, file names are:" + sourcePath, e);
		}
	}
}